-0.01x^2+1600=0

Solution for -0.01x^2+1600=0 equation:

-0.01x^2+1600=0

a = -0.01; b = 0; c = +1600;
Δ = b2-4ac
Δ = 02-4·(-0.01)·1600
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-0.01}=\frac{-8}{-0.02}
=+400
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-0.01}=\frac{8}{-0.02}
=-400
$